Solve the equation for the positive values of \(\theta\) less than 360o. 3 tan \(\theta\) + 2 = -1

a

135o or 315o

b

45o or 135o

c

315o or 180o

d

315v + 45o

e

360o or 315o

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Discussions (5)

Mrnoah
1 year ago

Let's break it down step by step:

Step 1: Isolate tan θ
3 tan θ + 2 = -1
Subtract 2 from both sides:
3 tan θ = -3
Divide both sides by 3:
tan θ = -1

Step 2: Find the angles
The tangent function is negative in the second and fourth quadrants.

The reference angle for tan θ = 1 is 45°.

Step 3: Find the angles in the correct quadrants
Second quadrant: θ = 180° - 45° = 135°
Fourth quadrant: θ = 360° - 45° = 315°

So, the solutions are θ = 135° and θ = 315°.

succy34
1 year ago

I don't understand

regony600
9 years ago

'D' is the answer tan135 wild never give you a positive answer

Asorockdsky
9 years ago

I thought so too... TanΦ being positive only in the first and third quadrants.

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