Solve the equation for the positive values of \(\theta\) less than 360o. 3 tan \(\theta\) + 2 = -1
a
135o or 315o
b
45o or 135o
c
315o or 180o
d
315v + 45o
e
360o or 315o
Explanation
Correct Option
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Discussions (5)

Mrnoah
1 year ago
Let's break it down step by step:
Step 1: Isolate tan θ
3 tan θ + 2 = -1
Subtract 2 from both sides:
3 tan θ = -3
Divide both sides by 3:
tan θ = -1
Step 2: Find the angles
The tangent function is negative in the second and fourth quadrants.
The reference angle for tan θ = 1 is 45°.
Step 3: Find the angles in the correct quadrants
Second quadrant: θ = 180° - 45° = 135°
Fourth quadrant: θ = 360° - 45° = 315°
So, the solutions are θ = 135° and θ = 315°.

Asorockdsky
9 years ago
I thought so too... TanΦ being positive only in the first and third quadrants.


