Find the solution of the equation x + 2\(\sqrt{x} - 8\) = 0
x + 2\(\sqrt{x} - 8 = 0, Let \sqrt{x} = y\) x = \(y^2\) \(y^2 + 2y\) - 8 = 0 (y + 4)(x - 2) = 0 y = -4 or 2 x = 16 or 4
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