Find the solution of the equation x + 2\(\sqrt{x} - 8\) = 0
a
(4, 16)
b
(2, 4)
c
(4, 1)
d
(1, 16)
e
(16, 16)
Explanation
Correct Option
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Jessica9876
2 months ago
X+2√X-8=0
let X be Y^2 and √X be Y
Y^2+2Y-8=0
(Y+4)(X-2)=0
Y=-4 or 2
remember our substitutions....
since Y=√X then:
X=(-4)^2 =16
X=2^2=4
correct answer is A✅
