If b = a + cp and r = ab + \(\frac{1}{2}\)cp2, express b\(^2\) in terms of a, c, r.
a
b2 = aV + 2cr
b
b2 = ar + 2c2r
c
b2 = a2 = \(\frac{1}{2}\) cr2
d
b2 = \(\frac{1}{2}\)ar2 + c
e
b2 = 2cr - a2
Explanation
Correct Option
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Discussions (3)
Anonymous2591606
1 year ago
i think the confusion is coming from the question, that "cp² part it's supposed to be (cp)²
i myself was confused because the answers i was getting wasn't even in the options
the png show what i got when i used (cp)²
richkid4ever07
1 year ago
Where was the ab when u placed the value of p from equation 1 to equation 2.
And secondly the value of p is meant to be (b-a)/c to make p the subject of the formula. But the c was no where to he found while trying to eliminate p
