Correct Answer: Option B

Explanation

Given that log\(_{10}\)2 = 0.3010, If 10\(^x\) = 0.2

log\(_{10}\)10\(^x\) = log\(_{10}\) 0.2 = x = log\(_{10}\)0.2

But 0.2 = 2 x 10\(^{-1}\), so log\(_{10}\)0.2 = log\(_{10}(2 \times 10^{-1})\), x =  log\(_{10}\)2 +  log\(_{10}\)10\(^{-1}\)

x = 0.3010 - 1

x = - 0.6990

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