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A.
x = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)
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B.
x = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)
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C.
x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)
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D.
x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)
Correct Answer: Option C
Explanation
bx\(^2\) + cx + a = 0
a = b; b = c; c = a
x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)
x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)
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