In a triangle PQT, QR = \(\sqrt{3}cm\), PR = 3cm, PQ = \(2\sqrt{3}\)cm and PQR = 30o. Find angles P and R

P = 60^o and R = 90^o

P = 30^o and R = 120^o

P = 90^o and R = 60^o

P = 60^o and R 60^o

P = 45^o and R = 105^o

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Ifennaoffor

3 years ago

The question is wrong
PR should have been root 3
and QR should have been 3
This change would correspond to your explanation.

Khadijahbintkhuwalid

1 year ago

The question I believe, suggests that it is an equilateral triangle, because ∠PQR=30 , so the other side is also 30. Additionally, the total angle∠PQT=60 . If one side measures 60, and a line QR divides the triangle, it automatically forms a right angle with the line PT, thus making ∠PRQ=90 . As a result, all the other angles are
60
I believe this is a typical JAMB question, and it shouldn’t take 2 minutes and 29 seconds to solve. That's why I tried to find the shortest and hopefully the most accurate way to solve it .....Wishing y'all success in JAMB