Factorize completely 81a\(^4\) - 16b\(^4\)

Mathematics

JAMB 1983

A. (3a + 2b)(2a - 3b)(9a² + 4b²)
B. (3a - 2b)(2a - 3b)(4a² - 9b²)
C. (3a - 2b)(3a + 2b)(9a² + 4b²)
D. (6a - 2b)(8a - 3b)(4a³ - 9b²)

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Correct Answer: Option C

Explanation

81a\(^4\) - 16b\(^4\) = (9a\(^2\))\(^2\) - (4b\(^2\))\(^2\)

= (9a\(^2\) + 4b\(^2\))(9a\(^2\) - 4b\(^2\))

N:B 9a\(^2\) - 4b\(^2\) = (3a - 2b)(3a + 2b)

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Factorize completely 81a\(^4\) - 16b\(^4\)

Correct Answer: Option C

Explanation

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