Make T the subject of the equation \(\frac{av}{1 - v}\) = \(\sqrt[3]{\frac{2v + T}{a + 2T}}\)
a
T = \(\frac{3av}{1 - v}\)
b
T = \(\frac{1 + v}{2a^2v^3}\)
c
T = \(\frac{2v(1 - v)^3 - a^4v^3}{2a^3v^3 + (1 - v)^2}\)
d
\(\frac{2v(1 - v)^3 - a^4 v^3}{2a^3v^ 3 - (1 - v)^3}\)
Explanation
Correct Option
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Discussions (11)
Anthony_Akaniyene
2 years ago
This is the correct equation and solution.
MySchool solution is correct but they wrote the question wrongly and the explanation isn't explanatory
Anthony_Akaniyene
2 years ago
the RHS of the equation was cube root not square root. MySchool did mistake in the question
