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If 0.0000152 x 0.00042 = A x 10\(^{B}\), where 1 \(\leq\) A < 10, find...

Mathematics
JAMB 1983

If 0.0000152 x 0.00042 = A x 10\(^{B}\), where 1 \(\leq\) A < 10, find A and B

  • A. A = 9, B = 6.38
  • B. A = 6.38, B = -9
  • C. A = -6.38, B = -9
  • D. A = -9, B = -6.38
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Correct Answer: Option B
Explanation

0.0000152 x 0.00042 = A x 10\(^{B}\)

1 \(\leq\) A < 10, it means values of A include 1 - 9

0.0000152 = 1.52 x 10\(^{-5}\)

0.00042 = 4.2 x 10\(^{-4}\)

1.52 x 4.2 = 6.384

10\(^{-5}\times 10^{-4}\)

= 10\(^{-5-4}\)

= 10\(^{-9}\)

= 6.38 x 10\(^{-9}\)

A = 6.38, B = -9


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JAMB CBT Software 2025 - Free Download
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JAMB CBT 2025 - Candidates, Schools, Centres, Resellers - Get Ready!
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JAMB CBT 2025 - Candidates, Schools, Centres, Resellers - Get Ready!
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