A straight line y = mx meets the curve y = x2 - 12x + 40 in two distinct points. If one of them is (5, 5) find the other
a
(5, 6)
b
(8, 8)
c
(8, 5)
d
(7,7)
e
(7, 5)
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Discussions (6)

SammyKush011
5 years ago
the solution given is generally correct but incomplete
x = 5 or 7
but points require both x and y values.
y = mx
when x = 5
y= 5 as given by question '(5,5)'
. : m = 1
since x = 7
y = 7*1 = 7
(7,7) D

willispark
1 year ago
Hi Samuel;
what if I substitute for the values
(7, 7) into y = x2 -12x + 40
it gives 7 != 7^2 -12(7) + 40
7 != 49 -84 + 40
7 != 5
I think both solutions are having commas. Though (7, 7) and (5, 5) satisfies y = mx but not the other.


