Correct Answer: Option B

Explanation

Area of trapezium = 14cm²

Area of trapezium = \(\frac{1}{2}\)(a + b)h

14 = \(\frac{1}{2}\)(4 + 3)h

14 = \(\frac{7}{2}\)h

h = \(\frac{14 \times 2}{7}\)

= 4

Area of SQR = \(\frac{1}{2}\)(3 x 4)

= \(\frac{12}{2}\)

= 6.0

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