Find the values of p for which the equation x\(^2\) - (p - 2)x + 2p + 1 = 0

a

(21, 0)

b

(0, 12)

c

(1, 2)

d

(3, 4)

e

(4, 5)

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Correct Option
b

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Discussions (7)

SLAZE5
1 year ago

Sharp! I understand it now, but the explanation looks a bit clustered up

Peter9695
3 years ago

I understand how they got twelve but how did they get 0?

From which topic in mathematics

FAECSB7610542
1 year ago

Pls was it mentioned in the question that the equation has equal roots?. That's what they're doing in the solution.

Banji206
2 years ago

please how did (-2)^2 turned to 4P? where did the p came from

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