Simplify \(\frac{1}{5x + 5}\) + \(\frac{1}{7x+ 7}\)
\(\frac{1}{5x + 5}\) + \(\frac{1}{7x+ 7}\) = \(\frac{1}{5(x + 1)}\) + \(\frac{1}{7(x + 1)}\) = \(\frac{7 + 5}{35(x + 1)}\) = \(\frac{12}{35(x + 1)}\)
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