Solve the equation 3x\(^2\) + 6x - 2 = 0
a
x = -1 \(\pm\) \(\frac{\sqrt{3}}{3}\)
b
x = -1 \(\pm\) \(\frac{\sqrt{15}}{3}\)
c
x = -2 \(\pm\) 2
d
x = 3 \(\pm\) \(\frac{\sqrt{3}}{15}\)
Explanation
Correct Option
bVideo Explanation
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