Make y the subject of the formula Z = x\(^2\) + \(\frac{1}{y^3}\)
a
y = \(\frac{1}{(Z - x^2)^3}\)
b
y = \(\frac{1}{(Z + x^2)^{\frac{1}{3}}}\)
c
y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)
d
y = \(\frac{1}{\sqrt[3]{Z} - \sqrt[3]{x^2}}\)
Explanation
Correct Option
cVideo Explanation
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