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PQR is a triangle in which PQ = 10cm and QPR = 60oS is a...

Mathematics
JAMB 1988

PQR is a triangle in which PQ = 10cm and QPR = 60oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of the perpendicular from S on PR, find the length SU in cm to one decimal place
  • A. 2.7
  • B. 4.33
  • C. 3.1
  • D. 3.3
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Correct Answer: Option B
Explanation
\(\bigtriangleup\)PUS is right angled

\(\frac{US}{5}\) = sin60o

US = 5 x \(\frac{\sqrt{3}}{2}\)

= 2.5\(\sqrt{3}\)

= 4.33cm

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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