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A.
\(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
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B.
\(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
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C.
\(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
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D.
\(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)
Correct Answer: Option C
Explanation
px2 + qx + b = 0
Using almighty formula
\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)
Where a = p, b = q and c = b
substitute for this value in equation (i)
= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
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