Simplify \(\frac{x + 2}{x + 1}\) - \(\frac{x - 2}{x + 2}\)

Mathematics

JAMB 1988

A. \(\frac{3}{x + 1}\)
B. \(\frac{3x + 2}{(x + 1)(x + 2)}\)
C. \(\frac{5x + 6}{(x + 1)(x + 2)}\)
D. \(\frac{2x^2 + 5x + 2}{(x + 1)(x + 2)}\)

WAEC offline past questions - with all answers and explanations in one app - Download for free

WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709

WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995

Correct Answer: Option C

Explanation

\(\frac{x + 2}{x + 1}\) - \(\frac{x - 2}{x + 2}\) = \(\frac{(x + 2)(x + 2) - (x -2) - (x - 2)(x + 1)}{(x + 1)(x + 2)}\)

= \(\frac{(x^2 + 4x + 4) - (x^2 - x - 2)}{(x + 1)(x + 2)}\) = \(\frac{x^2 + 4x + 4 - x^2 + x + 2}{(x + 1)(x + 2)}\)

= \(\frac{5x + 6}{(x + 1)(x + 2)}\)

Previous Next

Go back to Maths classroom

Report an Error Ask A Question Download App