Mathematics
JAMB 1988
Four interior angles of a pentagon are 90
o - x
o, 90
o + x
o, 110
o - 2x
o, 110
o + 2x
o. Find the fifth interior angle
-
A.
110o
-
B.
120o
-
C.
130o
-
D.
140o
Correct Answer: Option D
Explanation
Let the fifth interior angle be y: sum of interior angle of a pentagon
= (2 x 5 - 4) x 90o
= 6 x 90o
= 540o
(90 - x) + (90 + x) + (110 - 2x) + (110 + 2x) + y = 540o
400o + y = 540o
y = 540 - 400o
y = 140o
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