Simplify \(\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}\)
\(\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}\) = \(((64r^{-6})^{1/_2})^{1/_3}\) =\((64r^{-6})^{1/_6}\)
= (\(64)^{1/_6}(r^{-6})^{1/_6}\)
=\(\frac{2}{\text{r}}\)
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