The H.C.F. of a²bx + ab²x and a²b - b² is

Leinad321

3 years ago

The secomd par of their explanation was made up
how can you factorise
(a²b - b²) and get b(a² - b²)
that b(a² - b²) when the bracket is opened will give a²b - b³
please correct this

MikeMusic

10 months ago

either the answer is option A, or the question is wrong. Myschool pls rectify

prosperpat

2 months ago

Looking at the two expressions again:
​Expression 1: abx(a + b) → Factors outside are a, b, and x.
​Expression 2: b(a^2 - b) → Factor outside is b.
​The only factor common to both "outside" parts is b.
​However, as we noticed, for the answer to be a + b (Option B), the second expression must be written such that (a + b) can also be pulled "outside" through further factorization, like b(a - b)(a + b). In that specific case, b(a+b) would be the total factor common to both.

Ar1ana

4 months ago

the answer is A

Bunsgea

7 months ago

pls change the a² to a³, probably an error

Aganyaka

4 years ago

The solving is confusing and not understandable

Susanna01

3 months ago

the answer is obviously A

Ajibola1122

2 months ago

A lot is to be done about this answer sections