| No. defective per box | 4 | 5 | 6 | 7 | 8 | 9 |
| No. of boxes | 2 | 7 | 17 | 10 | 8 | 6 |
Find the percentage of boxes containing at least 5 defective bolts each
% of boxes containing at least 5 defective bolts each
= \(\frac{7 + 17 + 10 + 8 + 6}{50}\)
= \(\frac{48}{50}\) x \(\frac{100}{1}\)
= 96%
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