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What is the nth term of the progression 27, 9, 3,......?

Mathematics
JAMB 1991
What is the nth term of the progression 27, 9, 3,......?
  • A. 27\(\frac{1}{3}\) n - 1
  • B. 3n + 2
  • C. 27 + 18(n - 1)
  • D. 27 + 6(n - 1)
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Correct Answer: Option A
Explanation
Given 27, 9, 3,......this is a G.P

r = \(\frac{9}{27}\)

= \(\frac{1}{3}\)

T = arn - 1

= 27\(\frac{1}{3}\) n - 1
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