Simplify 2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9
1 - 4 log3
-1 + 2 log 3
-1 + 5 log2
1 - 2log 2
Explanation
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Discussions (14)
ans above is not crt
2log(⅖)—log⁷²/₁₂₅ + log9
log(⅖)²—log(⁷²/₁₂₅) + log 9
log(⁴/₂₅) - log (⁷²/₁₂₅) + log 9
log[(⁴/₅ ÷ ⁷²/₁₂₅)] × 9)]
log[(⁴/₂₅×¹²⁵/₇₂)]×9
log[(⁵/₁₈×⁹/₁)]
log[(⁵/₂)]
log(⁵/₂)
Ans is log5 - log 2
Everyone is right.
Usually the final answer is Log 5 - Log 2
But Myschool Organisation wants to make things tricky for somebody Soo what they did is
Log5 = Log (10/2)
= Log10 - Log2
Remember; Log10 = 1
So, Log5 = 1 - Log2
Substituting into the main expression
Log5 - Log2 = (1 - Log2) - Log2
= 1 - Log2 - Log2
= 1 - 2Log2
The rules used in the explanation was wrong though
The selected answer is wrong:
Can the Contributor to the answer explain how he/She got Log(10/40 and Log22 to the base of 10. Thank you.
