The probability of an event P is \(\frac{3}{4}\) while that of another event Q is \(\frac{1}{6}\). If the probability of both P and Q is \(\frac{1}{2}\). What is the probability of either P or Q.
Prob of P = \(\frac{3}{4}\)
Prob of Q = \(\frac{1}{6}\)
Prob of both P or Q = \(\frac{3}{4} + \frac{1}{6} = \frac{11}{12}\)
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