\(\begin{array}{c|c} \text{No. of children} & 0 & 1 & 2 & 3 & 4 &...

JAMB 1992

\(\begin{array}{c|c} \text{No. of children} & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text{No. of families} & 7 & 11 & 6 & 7 & 7 & 5 & 3 \end{array}\)
Find the mode and median respectively of the distribution above

A. 2, 1
B. 1, 2
C. 1, 5
D. 5, 2

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Correct Answer: Option B

Explanation

From the table, the mode = 1.

The median = 2.

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\(\begin{array}{c|c} \text{No. of children} & 0 & 1 & 2 & 3 & 4 &...

Correct Answer: Option B

Explanation

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