The radius of a circle is given as 5cm subject to an error of 0.1cm. What is the percentage error in the area of the circle?
% error in Area = \(\frac{\pi(5.1)^2 - \pi(5)^2 \times 100%}{\pi(5)^2}\)
= \(\frac{\pi 26.01 - 25 \times 100%}{\pi(25)}\)
= \(\frac{1.01}{25}\) x 100%
= 4.04%
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