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Make x the subject of the relation \(\frac{1 + ax}{1 - ax}\) = \(\frac{p}{q}\)

Mathematics
JAMB 1993
Make x the subject of the relation \(\frac{1 + ax}{1 - ax}\) = \(\frac{p}{q}\)
  • A. \(\frac{p + q}{a(p - q)}\)
  • B. \(\frac{p - q}{a(p + q)}\)
  • C. \(\frac{p - q}{apq}\)
  • D. \(\frac{pq}{a(p - q)}\)
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Correct Answer: Option B
Explanation
\(\frac{1 + ax}{1 - ax}\) = \(\frac{p}{q}\) by cross multiplication,

q(1 + ax) = p(1 - ax)

q + qax = p - pax

qax + pax = p - q

∴ x = \(\frac{p - q}{a(p + q)}\)
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts