If 9\(^{(x - \frac{1}{2})} = 3^{x^2}\) Find the value of x
9(x - \(\frac{1}{2}\)) 3x2 = 3\(^{2(x - \frac{1}{2})}\) = 3\(^x{^2}\) ∴ 2(x - \(\frac{1}{2}\)) = x2 2x - 1 = x\(^2\) hence x\(^2\) - 2x + 1 = 0 (x - 1)(x - 1) = 0 x = 1
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