In a triangle XYZ, if < XYZ is 60º, XY = 3cm, and YZ = 4cm, calculate the length of the side XZ.
(XZ)\(^2\) = 3\(^2\) + 4\(^2\) - 2 x 3 x 4 cos60º = 25 - 24\(\frac{1}{2}\) XZ = \(\sqrt{13}\)cm
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}