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Let f(x) = 2x + 4 and g(x) = 6x + 7 here g(x) >...

Mathematics
JAMB 1997

Let f(x) = 2x + 4 and g(x) = 6x + 7 here g(x) > 0. Solve the inequality \(\frac{f(x)}{g(x)}\) < 1
  • A. x < - \(\frac{3}{4}\)
  • B. x > - \(\frac{4}{3}\)
  • C. x > - \(\frac{3}{4}\)
  • D. x > - 12
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Correct Answer: Option C
Explanation
\(\frac{f(x)}{g(x)}\) < 1

∴ \(\frac{2x +4}{6x + 7}\) < 1

= 2x + 4 < 6x + 7

= 6x + 7 > 2x + 4

= 6x - 2x > 4 - 7

= 4x > -3

∴ x > -\(\frac{3}{4}\)

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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