Let f(x) = 2x + 4 and g(x) = 6x + 7 here g(x) > 0. Solve the inequality \(\frac{f(x)}{g(x)}\) < 1
a
x < - \(\frac{3}{4}\)
b
x > - \(\frac{4}{3}\)
c
x > - \(\frac{3}{4}\)
d
x > - 12
Explanation
Correct Option
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Havilah10
2 months ago
Very straightforward don't just forget the rule that says when dividing with the minus sign the sign (< or >) will change
