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Solve the simultaneous equations \(\frac{2}{x} - {\frac{3}{y}}\) = 2, \(\frac{4}{x} + {\frac{3}{y}}\) = 10

Mathematics
JAMB 1997

Solve the simultaneous equations \(\frac{2}{x} - {\frac{3}{y}}\) = 2, \(\frac{4}{x} + {\frac{3}{y}}\) = 10

  • A. x = \(\frac{3}{2}\), y = \(\frac{3}{2}\)
  • B. x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
  • C. x = \(\frac{-1}{2}\), y = \(\frac{-3}{2}\)
  • D. x = \(\frac{1}{3}\), y = \(\frac{3}{2}\)
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Correct Answer: Option B
Explanation

\(\frac{2}{x} - {\frac{3}{y}}\) = 2.....(1)

\(\frac{4}{x} + {\frac{3}{y}}\) = 10 ... (2)

(1) + (2):

\(\frac{6}{x}\) = 12 \(\to\) x = \(\frac{6}{12}\)

x = \(\frac{1}{2}\)

put x = \(\frac{1}{2}\) in equation (i)

= 4 - \(\frac{3}{y}\) = 2

= 4 - 2

= \(\frac{3}{y}\)

therefore y = \(\frac{3}{2}\)


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WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709