For what value of x does 6 sin (2x - 25)o attain its maximum value in the range 0o \(\leq\) x \(\leq\) 180o
y = 6 sin (2x - 25)º
\(\frac{dy}{dx}\) = 12 cos(2x - 25)º
\(\frac{dy}{dx}\) = 0
12 cos x (2x - 25º) = 0
= cos(2x - 25º) = 0
= 2x - 25º = cos\(^{-1}\)(0)
= 2x - 25º = 90º
x = \(\frac{115}{2}\)
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