In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities \(\frac{2}{5}\) and \(\frac{1}{3}\) respectively of winning the gold in the football event. What is the probability that either team will win the gold?
\(\frac{2}{15}\)
\(\frac{7}{15}\)
\(\frac{11}{15}\)
\(\frac{13}{15}\)
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please check the solution the question said either that is probaility one will win and the other fail or probability that the other will pass and the first will fail
It is not possible for the both teams to win the gold medal. Therefore, after summing the probabilities you are meant to subtract the probability of both teams winning from the answer initially obtained.
The reason for using this type of formula is because of both X and Y mutually exclusive event hmm
