Correct Answer: Option A

Explanation

mean (x) = \(\frac{\sum x}{N}\)

= k + k + 1 + k + 3

= \(\frac{3k + 3}{3}\)

= k + 1

\(\begin{array}{c|c} X & (X -X) & (X -X)^2\\ \hline k & -1 & 1 \\ k + 1 & 0 & 0\\ k + 2 & 1 \\ \hline & & 2\end{array}\)

Variance (52) = \(\frac{\sum (x - x)^2}{N}\)

= \(\frac{2}{3}\)

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