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Evaluate ∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx

Mathematics
JAMB 1998

Evaluate ∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx
  • A. \(\frac{\pi}{2}\)
  • B. \(\pi\) - 2
  • C. \(\frac{\pi}{3}\)
  • D. \(\pi\) + 2
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Correct Answer: Option B
Explanation
∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx

∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\)

= \(\pi\) - 2 + c

when c is an arbitrary constant of integration

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