If x is a positive real number, find the range of values for which \(\frac{1}{3x}\) + \(\frac{1}{2}\) > \(\frac{1}{4x}\)
a
x > -\(\frac{1}{6}\)
b
x > 0
c
0 < x < 4
d
0 < x < \(\frac{1}{6}\)
Explanation
Correct Option
dVideo Explanation
No video available
Post your Contribution
Share:
Discussions (7)
hafheez
7 years ago
A IS VERY COWET
1/3X +1/2>1/4X
SUBTRACT 1/2 AND 1/4X FROM BOTH SIDES
1/3X-1/4X>-1/2
1/12X>-1/2
MULTIPLY BOTH SIDES BY 12
1/X>-6
DIVDE BOTH SIDES BY 1
X>-1/6
L.P.R
1 year ago
¹/3x + ¹/2 >¹/4x
= (2+3x)/6x > 1/4x
C.M
= 4x(2 +3x) > 6x
=8x + 12x² > 6x
=12x² >6x - 8x
=12x² > -2x
Make x the subject of this eq.
Multiple though by 1/12x
X >-⅙
