Make \(\frac{a}{x}\) the subject of formula \(\frac{x + a}{x - a}\) = m

a

\(\frac{m - 1}{m + 1}\)

b

\(\frac{m + 1}{1 - m}\)

c

\(\frac{1 - m}{1 + m}\)

d

\(\frac{m + 1}{m - 1}\)

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Correct Option
a

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Discussions (12)

regony600
9 years ago

wrong question

Kamsi7
2 months ago

option a and c are the same. wrongly failed.

Themmythope1378
2 years ago

The numerator was solved as (x+a) in the solution but written as (x+1) in the question which makes it difficult to get the answer

abdulsalam.saliu
4 years ago

The question is wrongly composed. It is supposed to be x+a/x-a=m not x+1/X-a=m . It is even stated in the solution. kindly make due and necessary corrections.

harley victor
10 years ago

The question is wrongly composed:

nothing is given as to get the subject of the formula

REF: check the question

Myschool Kelly
9 years ago

Correction has been made. Thanks for your observations.

85770026HG
5 years ago

There is no “=m” in the question. Although I suppose I should have guessed since there was an “m” in every answer

Adex_14
1 year ago

(x + a)/(x - a) = m
mx - ma = x + a
mx - x = ma + a
x(m - 1) = a(m + 1)
a/x = (m + 1)/(m - 1)

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