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Find the value of k if \(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

Mathematics
JAMB 1998

Find the value of k if \(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)
  • A. 3
  • B. 2
  • C. \(\sqrt{3}\)
  • D. \(\sqrt 2\)
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Correct Answer: Option D
Explanation
\(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

\(\frac{k}{\sqrt{3} + \sqrt{2}}\) x \(\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}\)

= k\(\sqrt{3 - 2}\)

= k(\(\sqrt{3} - \sqrt{2}\))

= k\(\sqrt{3 - 2}\)

= k\(\sqrt{3}\) - k\(\sqrt{2}\)

= k\(\sqrt{3 - 2}\)

k2 = \(\sqrt{2}\)

k = \(\frac{2}{\sqrt{2}}\)

= \(\sqrt{2}\)

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