A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
Actual length of rope = 1.25m
Measured length of rope = 1.26m
error = (1.26 - 1.25)m - 0.01m
Percentage error = \(\frac{error}{\text{actual length}}\) x 100%
= \(\frac{0.01}{1.25}\) x 100%
= 0.8%
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