Mathematics
JAMB 2011
A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.
-
A.
195o
-
B.
135o
-
C.
225o
-
D.
045o
Correct Answer: Option B
Explanation
tan\(\theta\) = \(\frac{100}{100}\) = 1
\(\theta\) = tan
-1(1) = 45
o
The bearing of x from z is N45
oE or 135
o
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