Correct Answer: Option A

Explanation

6P^r = 6 Thus r = 1

N.B 6P¹ = \(\frac{\text{6!}}{\text{(6 - 1)!}}\)

= \(\frac{\text{6!}}{\text{5!}}\)

= \(\frac{6 \times \text{5!}}{\text{5!}}\) = 6

6P_{r + 1} = 6P₂ = \(\frac{\text{6!}}{(6 - 2)\text{!}} = \frac{6\text{!}}{\text{4!}}\)

= \(\frac{6 \times 5 \times \text{4!}}{\text{4!}}\)

= 30

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