Correct Answer: Option D

Explanation

\(\int^2_1(x^2 - 4x)dx\)

\((\frac{x^3}{3} - \frac{4x^2}{2})\)

substituting integrate values

\([\frac{8}{3} - \frac{4 \times 4}{2}] - [\frac{1}{2} - 2]\)

= \(-\frac{11}{3}\)

There is an explanation video available below.

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