\(\begin{array}{c|c} Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\...

JAMB 2014

\(\begin{array}{c|c}
Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
Frequency & 18 & 22 & 20 & 16 & 10 & 14
\end{array}\)

The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?

A. \(\frac{1}{5}\)
B. \(\frac{1}{2}\)
C. \(\frac{2}{5}\)
D. \(\frac{3}{4}\)

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Correct Answer: Option C

Explanation

Let E demote the event of obtaining at least a 4
Then n(E) = 16 + 10 + 14 = 40

Hence, prob (E) = \(\frac{n(E)}{n(S)}\)

\( = \frac{40}{100}\)

\( = \frac{2}{5}\)

There is an explanation video available below.

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