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A.
\(\frac{7!}{3!}\)
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B.
\(\frac{7!}{4!}\)
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C.
\(\frac{7!}{3!4!}\)
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D.
\(\frac{7!}{2!5!}\)
Correct Answer: Option C
Explanation
A team of 2 girls can be selected from 7 girls in \(^7C_3\)
\( = \frac{7!}{(7 - 3)! 3!}\)
\( = \frac{7!}{4! 3!} ways\)
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