If \(8^{x+1}=\frac{1}{4}\), find x
\(8^{x+1}=\frac{1}{4}\\ 2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\ 3x=-5\Rightarrow x = -\frac{5}{3}\)
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