Simplify: \(\frac{2}{3xy} - \frac{3}{4yz}\)
a
\(\frac{2-x}{12xyz}\)
b
\(\frac{2z-3x}{12xyz}\)
c
\(\frac{4z-3x}{12xyz}\)
d
\(\frac{8z-9x}{12xyz}\)
Explanation
Correct Option
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VictorEvogor0001
5 years ago
Something is wrong with the question.
2/(3xy) - 3/(yz)
==>(2(yz)-(9xy))/3x(y^2)z
==>factor y from dividend then cancel top and bottom y
==>(2z-9x)/3xyz
